ad is a median of a triangle abc prove that ab+ac>2ad
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according to Pythagoras property
ab^2-bd^2=ad^2
so automatically
ab-bd=ad
ac^2-cd^2=ad^2
so automatically
ac-cd=ad
so add equation 1,2
ac+an+(be+CD) =2ad
ac+ab= 2ad-bc
so thus proved ac+an is greater than 2ad
ab^2-bd^2=ad^2
so automatically
ab-bd=ad
ac^2-cd^2=ad^2
so automatically
ac-cd=ad
so add equation 1,2
ac+an+(be+CD) =2ad
ac+ab= 2ad-bc
so thus proved ac+an is greater than 2ad
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