AD is a median of the triangle ABC. Is it true that AB + BC + CA > 2 AD? Give reason for your answer.
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Given, △ABC, AD is median of triangle, on side BC
Now, In △ABD,
AB+BD>AD (Sum of two sides of triangle is greater than the third side)
Now, In △ACD,
AC+CD>AD (Sum of two sides of triangle is greater than the third side)
Thus, adding both,
AB+BD+AC+CD>2AD
AB+AC+BC>2AD
Hope it's help you :) ☺☺
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