AD is a median of triangle ABC and BL and CM are perpendiculars
kvnmurty:
perpendiculars from B and C onto AD respectively... prove BL = CM
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see diagram.
ABC is a triangle. AD is the median from A on to BC. BD = DC.
Area of triangle ABD = 1/2 BD * AE (altitude.
Area of triangle ADC = 1/2 DC * AE (altitude of triangle ADC also)
As BD = DC, the median divides the triangle into two equal parts (areas) ABD and ADC.
Now look at the area of triangle ABD with AD as the base. Area = 1/2 AD * BL
Area of triangle ADC with AD as the base = 1/2 AD * CM
Since the areas are equal, CM = BL
ABC is a triangle. AD is the median from A on to BC. BD = DC.
Area of triangle ABD = 1/2 BD * AE (altitude.
Area of triangle ADC = 1/2 DC * AE (altitude of triangle ADC also)
As BD = DC, the median divides the triangle into two equal parts (areas) ABD and ADC.
Now look at the area of triangle ABD with AD as the base. Area = 1/2 AD * BL
Area of triangle ADC with AD as the base = 1/2 AD * CM
Since the areas are equal, CM = BL
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