Question

AD is a median of triangle ABC the bisectors of Angle ADB and angle ADC meet at AB and AC in E and F respectively.prove that EF parallel to BC​

Answer 1

Heyaa♡♡

In ΔDAB, DE bisects ∠ADB

∴ DA/ DB = AE/EB -- (1)

In ΔDAC, DF bisects ∠ ADC

∴ DA/DC = AF/FC

=> DA/DB = AF/ FC --- (2)

From (1) and (2) we will get

AE/EB = AF/FC

In ΔABC

EF║BC

Hope it helped you.

Answer 2

Answer:

Hey Buddy here's ur answer