Question

AD is a median of triangle ABC. then AB+BC+CA is greater than 2AD

Answer 1

in triangle ABD
AB+BD>AD .......... (1)[sum of 2 sides of a triangle is greater than the third side]
in triangle ACD
AC+CD>AD .......... (2)[sum of 2 sides of a triangle is greater than the third side]
adding (1) & (2)
AB+BC+AC>2AD[BD+DC=BC]

Answer 2

In triangle ABC AD is the median AD is perpendicular on BC then, IN ABD AB+BD greater than AD ( sum of two sides is greater than third side )...1. in triangle adc A C + D C is greater than a d (sum of two sides is greater than the third side )....2. add equation first and second. AB +BD +AC+DCgreater than AD + AD then AB+bc+ac greater than 2AD