Question

AD is altitude of an isosceles triangle ABC in which AB=AB=30cm and BC=36.A point O is marked on AD in such a way that angle BOC=90 degree. find the area of quadrilateral ABOC.​

Answer 1

Answer:shuffle

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Answer 2

Answer:

wait a sec . what! ab=ab=30cm

423 cm² is the area

Step-by-step explanation:

AD=✓30²-18²=✓576=24

Area of ∆ABC=1/2xPerp.xBase=432...

Area of ∆BOC=1/2x✓18x✓18=9..

Area of quadilateral ABOC=Area of ∆ABC-Area of ∆BOC= 432-9=423cm²