Question

AD is altitude of equilateral triangle ABC. On AD as base another equilateral triangle ADE is constructed. Prove that area of triangle ADE: area of triangleABC = 3:4

Answer 1

here is a solution to your answer

Answer 2

Here is your answer dear

Let each side be a

Ab square=Ad square+ Bd square

a square= Ad square+ a square/2 whole square

a square= 4 Ad square+a square/ 4

4a square - a square/4 = ad square

√3/2=ad