Ad is an altitude of a triangle abc and bisects bc. Show that ab=ac
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Answered by
1
to prove the congruency
angle bad=angle adc
bd=bc
ad=ad
therefore by sas criteria triange bad is congruent to triangle dac
by cpct
ab=ac
angle bad=angle adc
bd=bc
ad=ad
therefore by sas criteria triange bad is congruent to triangle dac
by cpct
ab=ac
Answered by
0
Given
AD_|_BC & BD=CD
Now,
In tri(ADB) & tri(ADC)
AD =AD comon
BD=CD given
Therefore tri(ADB) congruence to tri(ADC)
Hence ,
AB=AC by cpct
AD_|_BC & BD=CD
Now,
In tri(ADB) & tri(ADC)
AD =AD comon
BD=CD given
Therefore tri(ADB) congruence to tri(ADC)
Hence ,
AB=AC by cpct
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