Question

AD is an altitude of an equilateral triangle ABC. On AD as base another
equilateral triangle ADE is constructed. Prove that ar(AMDE) : ar(AABC)
= 3:4.
@.v.##
v@..*​

Answer 1

Answer:

Here is your answer dear

Let each side be a

Ab square=Ad square+ Bd square

a square= Ad square+ a square/2 whole square

a square= 4 Ad square+a square/ 4

4a square - a square/4 = ad square

√3/2=ad