Question

Ad is an altitude of an equilateral triangle abc.On ad as a base another euilateral triangle ade is constructed .Prove that area(∆ade):area(∆abc)= 3:4

Answer 1

In the figure TriangleABC and TriangleADE are equilaterals

AD is altitude

AB=BC=AC=x (say)

refer 2nd and 3rd attachment for the next steps..

Thank me