Question

- AD is an altitude of an isosceles AABC in which AB = AC. Show that
i) AD biscts BC
(ii) AD bisects ZA​

Answer 1

Answer:

In ∆ ABD & ∆ACD

AB=AC. (given)

AD =AD. (common)

L ADB=L ADC. (90⁰)

∆ABD = ∆ACD (RHS)

i) BD= DC ( CPCT)

therefore AD bisects BC

ii) L BAD =L CAD. (CPCT)

therefore AD bisects L A

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