AD is an altitude of an isosceles triangle ABC in which AB=AC. Show that AD bisects BC
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Step-by-step explanation:
Given: Triangle abc is isosceles
Ab=Ac
to prove: Ad bisects bc
proof: in triangle abd and acd
ab=ac(given)
angle b=angle c(isosceles triangle property)
ad=ad(common)
triangle abd ≈ triangle acd (sas)
ad=dc
hence proved ad bisects bc
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