Math, asked by khushbir, 1 year ago

AD is an altitude of an isosceles triangle ABC in which AB=AC. Show that AD bisects BC​

Answers

Answered by dhr1309
2

Step-by-step explanation:

Given: Triangle abc is isosceles

Ab=Ac

to prove: Ad bisects bc

proof: in triangle abd and acd

ab=ac(given)

angle b=angle c(isosceles triangle property)

ad=ad(common)

triangle abd ≈ triangle acd (sas)

ad=dc

hence proved ad bisects bc

Answered by Anonymous
1

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