Question

AD is an altitude of an isosceles triangle ABC in which AB=AC.show that AD bisects BC

Answer 1

Given:-
ABC is a isosceles triangle.
AD is perpendicular on BC.
AB=BC
To prove:-
In Triangle ACD AND ABD,
AD=AD (Common)
AC=AB (Given)
Angle ADC=Angle ADB (90 degree
each)
Hence,Triangle ACD=ABD (By SAS)
Therefore,AD bisects BC. (By
C.P.C.T.)
HENCE,PROVED.

Answer 2

here is your answer