Question

AD is an altitude of an isosceles triangle ABC in which AB=AC show that 1) AD bisects BC 2) AD bisects angle A​

Answer 1

Answer:

This is your answer.......

Answer 2

Answer:

Step-by-step explanation:ABC is a isosceles triangle.

AD is perpendicular on BC.

AB=BC

To prove:-

In Triangle ACD AND ABD,

AD=AD (Common)

AC=AB (Given)

∠ ADC=∠ADB (90 degree each)

Δ ACD= ΔABD (By SAS)

Therefore,AD bisects BC AS WELL ∠A . (By CPCT)

HENCE,PROVED.