Question

AD is an altitude of an isosceles triangle ABC in which AB=AC . Show that - 1. AD bisects BC . 2 AD bisects angle A​

Answer 1

GivEn:-

• AD is an altitude of an isosceles triangle ABC in which AB = AC.

To ProvE:-

1. AD bisects BC
2. AD bisects ∠A

SoluTion:-

i) In right angled ∆ADB and ∆ADC,

AB = AC [GivEn]

AD = AD [Common]

∠ADB = ∠ADC [90°]

∴ ∆ADB ≅ ∆ADC [RHS rule]

∴ BD = CD [C.P.C.T.]

→ AD bisects BC.

ii) ∵ ∆ADB ≅ ∆ADC [Proved in (i) above]

∴ ∠BAD = ∠CAD [C.P.C.T.]

→ AD bisects ∠A.

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Answer 2

Step-by-step explanation:

Hope it will help you....