Question

AD is an altitude of an isosceles triangle ABC in which AB= AC show that ad bisects BC​

Answer 1

Given:-

ABC is a isosceles triangle.

AD is perpendicular on BC.

AB=BC

To prove:-

In Triangle ACD AND ABD,

AD=AD (Common)

AC=AB (Given)

Angle ADC=Angle ADB (90 degree

each)

Hence,Triangle ACD=ABD (By SAS)

Therefore,AD bisects BC. (By

C.P.C.T.)

HENCE,PROVED.

Answer 2

CRM

PLEASE CHECK YR ANSWER CAREFULLY

HOPE IT HELPS TO U

PLEASE MARK ME AS BRAINLIST