Question

AD is an altitude of an isosceles triangle ABC in which AB=AC. Show that i). AD bisects angle A ii). AD bisects BC.​

Answer 1

Answer:

In triangle ABD AND in triangle ACD

AB=CD (AS ISOCELES TRIANGLE)

ALSO ANGLE ADB =angleADC =90°

AND BD =DC

SO triangle ABD=triangle ADC

SO AD bisects angle A ( BY CPCT )

if it is proved then similarly AD ALSO BISECTS BC.

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Answer 2

Step-by-step explanation:

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