Question

AD is an altitude of an isosceles triangle ABC in which AB=AC ,Show that (I) AD bisects BC and (ii) AD bisects <A​

Answer 1

Step-by-step explanation:

proof:-

in triangle ADB and triangle ABC

∆ADC=∆ADB=90° ...( both 90°)

AB=AC ...(from 1)

AD = AD ...(common)

dear 4 triangle ADB congruent triangle ADC .

hence,by c.a.c.t.,

=> BD = DC

& angle BAC = angle BAC.

Answer 2

Answer:

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