Question

AD is an altitude of an isosceles triangle ABC in which AB=AC.show that AD bisects angle A.​

Answer 1

Answer:

ABC is isosceles triangle AB=AC

AD is altitude angle ADB angle ADC=90°

To prove,

AD bisect BC

AD bisect angle .A

proof,

angle ADB angle ADC

angle ADB is equal to angle ADC

AD is equals to AC

AD is equals to AD.

by RHS congruency

angle ADB and angle ADC.

by C.P.C.T.

BD is equal to CD.

angle BAC angle CAD.

hence proof.

Step-by-step explanation:

hope it helps you