Question

AD is an altitude of an isosceles triangle ABC in which AB=AC show that Triangle ABC is an isosceles triangle.​

Answer 1

Answer:

(i) AD bisects BC (ii) AD bisects ∠A. Let's construct an isosceles triangle ABC in which AB = AC as shown below. Hence, AD bisects BC. Hence, AD bisects ∠A.

Step-by-step explanation:

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