Question

AD is an altitude of an isosceles triangles ABC in which AB=AC. show that

a) AD bisects BC
b) AD bisects angleA​

Answer 1

Answer:

a

let adb and adc be saperate triangles

congruency between both triangles

ab=ac

ad is common

angle A is common

∆adb ≈∆adc by sas

so we can say ad is dividing ∆abc into two triangles

thus,,ad bisects bc

b)

by cpct, angle a is divided by ad ,so we can say that ad bisects angle a