Question

AD is an altitude of an isosceles tringleABC in which AB=AC.show that AD bisects BC

Answer 1

Step-by-step explanation:

In ∆ ABD &∆ ACD

<ABD=<ACD ( the angles opposite to equal sides are equal)

AB=AC(given)

AD=AD(common side)

∆ABD~∆ACD

so,ADB=ADC(90°) & BC=DC(corresponding parts of congruent triangle)

so,AD, bisector of BC