Question

AD is an altitude of an isosceles tringleABC in which AB=AC.show that AD bisects BC

Answer 1

Answer:

lets draw the figure( see file attached below)

Here,In ΔABC,

AC=AB.......................Isosceles triangle-2 sides are equal

∠B=∠C.........................   Isosceles triangle- angles opposite to the equal                      sides are equal.

AD=DA...........................Common.

∴ΔADC≅ΔADB.

CPCT, CD=DB.

If CD=DB , AD bisects BC.

HENCE PROVED>

HOPE ITT HELPS :D