Math, asked by hariprasath678, 6 months ago

AD is an altitude of an isoscolos triangle
ABC in which AB-AC. Prove that AngleBAD=AngleDAC

Answers

Answered by iamsadafhasan

2

Answer:

Hello

Step-by-step explanation:

Here's your answer, Check it.

Attachments:

Previous Question

Next Question

Similar questions

English, 3 months ago

I am a five letter word if you drop the first letter and the fourth letter from my name it will be the name of a colour...

Math, 3 months ago

the mode of the data set 4,8,4 ,11,4,7 is...

English, 3 months ago

What Poetic Device Is Used In The Poem “The Moon” By R.L Stevenson...

Math, 6 months ago

hcf of 72, 91, 38, 40...

English, 6 months ago

what is the meaning of 'twilight existence'?

Math, 11 months ago

triangle ABC is right angle at a is draw perpendicular to BC if ab is equal to 5 cm and ac is equal to 12 cm find the area of triangle abc also find the length of a d...

English, 11 months ago

she switched on the light. change the voice...

Science, 11 months ago

Draw the flow diagram of garbage collection lifecycle?