Math, asked by kaurdhaliwal2005, 9 months ago

AD is an altitude of isosceles triangle ABC , then ∆ABD ≅ ∆ACD by


ASA

RHS

SAS

All of above​

Answers

Answered by DhruvTanna13
1

Step-by-step explanation:

This is your answer for the question you asked.The last one is rhs test

Attachments:
Answered by Gautam200516
1

Answer:

Given: AB= AC, <ADB and <ADC = 90⁰

ASA: <B = <C (Side are equal so angle are also equal)

AD=AD (Common)

<ADB=<ADC (Given)

Hence proved that they are congruent by ASA.

RHS: <ADB=<ADC (Given)

AB=AC ( Given)

AD=AD (Common)

Hence proved that they are congruent by RHS

SAS: BD=CD (Angles are equal so, side is also equal)

<ADB=<ADC (Given)

AD=AD(Common)

Hence proved that they are congruent by SAS

So, All of the above is the correct answer.

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