Question

AD is diameter of a circle and AB is a chord. If AD= 34 cm, AB = 16cm the distance of AB from the centre of the circle is
a. 17 cm
b. 15 cm
c. 23 cm​

Answer 1

Answer:

Step-by-step explanation:

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX= 2/30 ​  

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴AO^2 =OX ^2 +AX  ^2

⇒17  ^2 =OX ^ 2  +15  ^2

OX  ^2 =17  ^2 −15  ^2

OX  ^2 =  root 64

​⇒OX=8cm