Question

Ad is diameter of a circle and ab is a chord. if ad = 34 cm, ab = 30 cm, then the distance of ab from the centre of the circle is

Answer 1

consider the center to be = O
then distance AO will be = 34/2= 17
now triangle AOB is isosceles triangle so AO = OB
now using Pythagoras theorem we can find the distance
15^2+ D^2=17^2
D=√64=8 cm

hope it helps

Answer 2

Answer:

8 cm

Step-by-step explanation:

consider the center to be = O

then distance AO will be = 34/2= 17

now triangle AOB is isosceles triangle so AO = OB

now using Pythagoras theorem we can find the distance

15^2+ D^2=17^2

D=√64=8 cm