Question

AD is diameter of a circle and AB is a chord. If AD=34cm, AB=30cm then the distance of AB from the

centre of circle is​

Answer 1

Step-by-step explanation:

Since the diameter AD = 34 cm., radius of the circle is 17 cm. Since AM = BM and AB = 30 cm, we have AM = BM = 15 cm. OM = 8. Distance of the chord from the centre is 8 cm.

Answer 2

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• Chord AB = 30 cm
• Diameter AD = 34 cm
• Radius = 34 / 2 = 17 cm

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➣ Dram OM ⊥ AB as shown in the figure.

➣ 2AM = AB [Perpendicular drawn from the center bisects the chord]

➣ AM = 30 / 2 = 15 cm

➣ By Pythagoras Theorem in Δ AOM:

➣ OM² + AM² = OA²

➣ OM² + 15² = 17²

➣ OM² = 289 - 225

➣ OM² = 64 cm

➣ OM = √64

➣ OM = 8 cm

Hope it helps..♪