ad is drawn perpendicular to base bc of a equilateral triangle abc.given bc=10cm,find the length of ad
DonDj:
√75 is the answer
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HERE IS THE SOLUTION;
◆ In The Given Figure;
In Equilateral ∆ ABC,
AB = BC = AC. 【 Equal Sides Of The Eq. Triangle 】
◆ To Find;
AD =?
◆ Solution;
In ∆ ABD,
AB = 10 Cm
BD = 5 Cm 【 Perpendicular On A Line Segment Divide It Into Two Equal Parts.】
AD = ?
By Applying Pythagoras Theorem, We Get;
AB^2 = BD^2 + AD^2
(10)^2 = (5)^2 + AD^2
=> 100 = 25 + AD^2
=> 100 - 25 = AD^2
=> 75 = AD^2
=> √75 = AD
=> AD = 8.66 Cm (Approx.)
◆ So the length of AD is √75 Cm Or 8.66 Cm ◆
HOPE IT HELPS
◆ In The Given Figure;
In Equilateral ∆ ABC,
AB = BC = AC. 【 Equal Sides Of The Eq. Triangle 】
◆ To Find;
AD =?
◆ Solution;
In ∆ ABD,
AB = 10 Cm
BD = 5 Cm 【 Perpendicular On A Line Segment Divide It Into Two Equal Parts.】
AD = ?
By Applying Pythagoras Theorem, We Get;
AB^2 = BD^2 + AD^2
(10)^2 = (5)^2 + AD^2
=> 100 = 25 + AD^2
=> 100 - 25 = AD^2
=> 75 = AD^2
=> √75 = AD
=> AD = 8.66 Cm (Approx.)
◆ So the length of AD is √75 Cm Or 8.66 Cm ◆
HOPE IT HELPS
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hope it helps u well
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