Question

ad is drawn perpendicular to base bc of a equilateral triangle abc.given bc=10cm,find the length of ad

Answer 1

HERE IS THE SOLUTION;

◆ In The Given Figure;

In Equilateral ∆ ABC,

AB = BC = AC. 【 Equal Sides Of The Eq. Triangle 】

◆ To Find;

AD =?


◆ Solution;

In ∆ ABD,

AB = 10 Cm

BD = 5 Cm 【 Perpendicular On A Line Segment Divide It Into Two Equal Parts.】


AD = ?

By Applying Pythagoras Theorem, We Get;



AB^2 = BD^2 + AD^2

(10)^2 = (5)^2 + AD^2

=> 100 = 25 + AD^2

=> 100 - 25 = AD^2

=> 75 = AD^2

=> √75 = AD

=> AD = 8.66 Cm (Approx.)

◆ So the length of AD is √75 Cm Or 8.66 Cm ◆


HOPE IT HELPS

Answer 2

Answer:

hope it helps u well

Step-by-step explanation:

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