AD is drawn perpendicular to base BC of an equilateral triangle ABC.Given BC find the length of AD
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Visualizing the question in mind,
In ADB,
AB^2=AD^2+BD^2
since AB=BC, &BD =1/2 BC (by cpct)
BC^2=AD^2+ 1/4 BC^2
AD^2=BC^2 - 1/4BC^2
AD^2 = 3/4 BC^2
Therefore , if BC is given (a side of an equilateral ) ,then,
AD = (√3/2) * (BC)
[For an eqiulateral ABC, whose height, is h or AD]
In ADB,
AB^2=AD^2+BD^2
since AB=BC, &BD =1/2 BC (by cpct)
BC^2=AD^2+ 1/4 BC^2
AD^2=BC^2 - 1/4BC^2
AD^2 = 3/4 BC^2
Therefore , if BC is given (a side of an equilateral ) ,then,
AD = (√3/2) * (BC)
[For an eqiulateral ABC, whose height, is h or AD]
JohalLoveleen:
Thank u so much!
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