) AD is drawn perpendicular to BC, base of an
equilateral triangle ABC. Given BC= 10 cm, find
the length of AD, correct to I place of decimal.
(ICSE) . Chap . pithagorus therom
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Step-by-step explanation:
ABC is an equilateral triangle.
AB=BC=CA=10 cm
AD is perpendicular
Therefore,
BD = 1/2 BC
BD =5 cm
BD=DC=5cm
By Pythagoras
AD×AD + DC × DC = CA×CA
AD×AD + 5×5 = 10×10
AD×AD + 25 = 100
AD×AD = 75
AD = √75
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