AD is drawn perpendicular to BC, base of an
equilateral triangle ABC. Given BC = 10 cm, find
the length of AD, correct to 1 place of decimal.
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Answer:
In ∆ABC
AB = BC = AC = 10 cm
AD is perpendicular of BC
BD=CD (∆ABC is an Equilateral Triangle)
BC= BD+CD
10 = BD + BD (BD=CD)
10 = 2 x BD
BD = 5 cm
in Right angle Triangle ∆ADB (<B = 90⁰)
(AB)² = (AD)² + (BD)² ( By Pythagorean )
(10)² = (AD)² + (5)²
100 = (AD)² + 25
100 - 25 = (AD)²
√75 = AD
AD = 8.66 cm
Step-by-step explanation:
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