AD is is perpendicular on base BC of an isosceles triangle ABC in which AB = AC. Show that
(i) Line segment AD bisects BC
(ii) AD bisects angle A
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GIVEN
AC=AB because it is a isoceles triangle
<C=<B becaus it is isoceles triangle
In triangle ADB AND ADC
AB=AC (GIVEN)
<ADB=<ADC (90°)
AD=AD. (COMMON)
SO BY AAS CONGRUENCE RULE
ADB=~ADC
BD=CD {CPCT}
SO AD BISECTS BC
<BAD=<CAD [CPCT]
SO AD BISECTS <A
AC=AB because it is a isoceles triangle
<C=<B becaus it is isoceles triangle
In triangle ADB AND ADC
AB=AC (GIVEN)
<ADB=<ADC (90°)
AD=AD. (COMMON)
SO BY AAS CONGRUENCE RULE
ADB=~ADC
BD=CD {CPCT}
SO AD BISECTS BC
<BAD=<CAD [CPCT]
SO AD BISECTS <A
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Answered by
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This is 2 question of ex 7.3 from maths 9th NCERT Textbook
In ∆ ADC & ∆ ADB
angle ADC=angle ADB (given perpendicular)
angleACD=angleABD (isosceles∆)
AB=AC(given)
: . ∆ ADC congruent to ∆ADB
by CPCT CD=DB
angle CAD=angle DAB
In ∆ ADC & ∆ ADB
angle ADC=angle ADB (given perpendicular)
angleACD=angleABD (isosceles∆)
AB=AC(given)
: . ∆ ADC congruent to ∆ADB
by CPCT CD=DB
angle CAD=angle DAB
Attachments:
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