AD is median andBL ,CM are perpendiculars drawn from B,C resp. on AD amdAD produced . proveBL=CN
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inΔBDL and ΔCDM,
∠BLD=∠CMD(both equal to 90°)
∠BDL=∠CDM (vetically opposite angles are equal)
BD=CD(AD is median)
∴ΔBDL≡ΔCDM(AAS conguency)
⇒BL=CM(cpct,corresponding parts of congruent triangles)
hence proved
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