Question

AD is median of ΔABC, where coordinates of B and C are respectively (4, 1) and (1, 6), then coordinates of D are​

Answer 1

$Given \: AD \: is \: a \: median \: of \: \triangle ABC, \\Where \: Coordinates \:of \: B \: and \: C \\are \: (4,1) \: and \: (1,6) \: respectively$

$Let \: B(4,1) = ( x_{1}, y_{1}) \: and \\C(1,6)= ( x_{2}, y_{2})$

$Coordinates \: D \\= Mid \: point \: of \: BC \\= \Big( \frac{x_{1} + x_{2}}{2} , \frac{y_{1} + y_{2}}{2} \Big) \\= \Big( \frac{4+1}{2} , \frac{1+6}{2}\Big) \\= \Big( \frac{5}{2} , \frac{7}{2}\Big)$

Therefore.,

$\red{Coordinates \: D}\green{ = \Big( \frac{5}{2} , \frac{7}{2}\Big)}$

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