Question

AD is one of the medians of a triangle ABC and P is point on AD. prove ar(BDP) = ar(CDP)

Answer 1

Answer:

Step-by-step explanation:

Since median divides a triangle into two equal parts with equal area,

ar(ABD)=ar(ACD)----1

since p is any point on median,

ar(ABP)=ar(ACP)------2

subtracting 2 from 1

ar(ABD)- ar(ABP)= ar(ACD)- ar(ACP)

ar(BDP) =ar(CDP)

Answer 2

Answer:

in the adjoining figure the area is one of the medians of a triangle ABC and P is a point on a d prove that area of triangle BDP equal to area of triangle CDP and (ii) area of triangle ABC is equal to area of triangle ACP