AD is parallel to CD find x
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Let us draw a line EF parallel to the lines AB and CD.
Then ∠BPF=∠ABP=48 o
[ alternate angle].......(1).
Also, ∠CPF=∠PCD=24 o
[ alternate angle]......(2).
Now
∠BPC=∠BPF+∠CPF=48 o+24 o =72 o .
Then x=360 o −72 o =288 o
.
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here is. u r answer mate
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