Question

AD is the diameter of a circle and AB is a chord. If AD=50cm, AB=48cm, then the distance of AB from the centre of the circle is:

1 point

5cm

7cm

6cm

8cm​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX=

2

30

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴AO

2

=OX

2

+AX

2

⇒17

2

=OX

2

+15

2

⇒OX

2

=17

2

−15

2

⇒OX

2

=

64

⇒OX=8cm