AD is the diameter of a circle of length 34 cm. AB is a chord of length 30 cm. find the distance of AB from centre of circle
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Since the diameter AD = 34 cm., radius of the circle is 17 cm. Since AM = BM and AB = 30 cm, we have AM = BM = 15 cm. OM = 8. Distance of the chord from the centre is 8 cm.
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Step-by-step explanation:
ΔAMC is a right triangle. Since the diameter AD = 34 cm., radius of the circle is 17 cm. Since AM = BM and AB = 30 cm, we have AM = BM = 15 cm
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