AD is the diameter of a circle of radius 6 cm and AB=BC =CD. semi - circle are drawn with AB and BD as diameter as shown in the figure. find the perimeter and area of the shaded region
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AD=6*2=12 cm
thus are of semicircle made on base AD
A1=pi/2*6^2
=56.52 cm^2
sibnce AB=BC=CD
Thus we can say that
AB=AD/3
12/3
AB=4cm
thus area of semicircle dawn on base AB
A2=pi/2*4
=6.28cm^2
Similarly
Area of semicircle draw on base BD
A3=pi/2*16
25.12 cm^2
thus area of shaded region
A=A1-A3+A2
A=56.52-25.12+6.28
A=37.68 cm^2
I hope it helps you,
mark brainliest please.
thus are of semicircle made on base AD
A1=pi/2*6^2
=56.52 cm^2
sibnce AB=BC=CD
Thus we can say that
AB=AD/3
12/3
AB=4cm
thus area of semicircle dawn on base AB
A2=pi/2*4
=6.28cm^2
Similarly
Area of semicircle draw on base BD
A3=pi/2*16
25.12 cm^2
thus area of shaded region
A=A1-A3+A2
A=56.52-25.12+6.28
A=37.68 cm^2
I hope it helps you,
mark brainliest please.
akash8627:
right answer
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