ad is the diameter of a circle of radius 6 cm and ab is equal to BC is equal to CD semi circles are drawn with ab and BD are diameters as shown in the figure find the perimeter and area of the shaded region
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where is the figure mate!!...
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6
Answer:
AD=6*2=12 cm
thus are of semicircle made on base AD
A1=pi/2*6^2
=56.52 cm^2
sibnce AB=BC=CD
Thus we can say that
AB=AD/3
12/3
AB=4cm
thus area of semicircle dawn on base AB
A2=pi/2*4
=6.28cm^2
Similarly
Area of semicircle draw on base BD
A3=pi/2*16
25.12 cm^2
thus area of shaded region
A=A1-A3+A2
A=56.52-25.12+6.28
A=37.68 cm^2
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