Question

AD is the median of a ∆ABC ,prove that AB+BC+CA>2AD

Answer 1

Answer:

Given, △ABC, AD is median of triangle, on side BC

Now, In △ABD,

AB+BD>AD (Sum of two sides of triangle is greater than the third side)

Now, In △ACD,

AC+CD>AD (Sum of two sides of triangle is greater than the third side)

Thus, adding both,

AB+BD+AC+CD>2AD

AB+AC+BC>2AD