Question

AD is the median of a ∆ABC, prove that AB+BC+CA>2AD​

Answer 1

Answer:

Yes

Step-by-step explanation:

i)In ABD,We have= AB+BD>AD

(Sum of any 2 sides of a triangle is greater than the third side)

ii)In ACD,We have= AC+CD>AD

(Same formula as above)

On adding Eqs i and ii,we get

(AB+BD+AC+CD)>2 AD

(AB+BD+CD+AC)>2 AD

AB+BC+AC> 2 AD