AD is the median of a ∆ABC, prove that AB+BC+CA>2AD
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Answer:
Yes
Step-by-step explanation:
i)In ABD,We have= AB+BD>AD
(Sum of any 2 sides of a triangle is greater than the third side)
ii)In ACD,We have= AC+CD>AD
(Same formula as above)
On adding Eqs i and ii,we get
(AB+BD+AC+CD)>2 AD
(AB+BD+CD+AC)>2 AD
AB+BC+AC> 2 AD
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