Question

AD is the median of.∆ABC,prove that AB+AC is greater then 2AD

Answer 1

it can be proved by the following method

Answer 2

Given:

AD is the median of ΔABC.

To prove:

AB + AC > 2AD

Construction

Produce AD to E such that AD = DE. Join CE.

Proof:

In ΔABD and ΔCDE

AD = DE (Construction)

∠ADB = ∠CDE (Vertically opposite angles)

BD = DC (AD is the median from A to BC)

∴ ΔABD ΔCDE (SAS congruence criterion)

⇒ AB = CE (CPCT) ...(1)

In ΔACE,

AC + CE > AE (Sum of any two sides of a triangle is greater than the third side)

⇒ AC + AB > AD + DE [Using (1)]

⇒ AC + AB > AD + AD (Constriction)

⇒ AC + AB > 2AD

hope it helps you❤

~~Anushka Here