AD is the median of an equilateral triangle ABC. Prove
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To prove: The medians of an equilateral triangle are equal.
Median = The line joining the vertex and mid-points of opposite sides.
Proof: Let Δ ABC be an equilateral triangle
AD, EF and CF are its medians.
Let,
AB = AC = BC = x
In BFC and CEB, we have
AB = AC (Sides of equilateral triangle)
AB = AC
BF = CE
∠ABC =∠ACB (Angles of equilateral triangle)
BC = BC (Common)
Hence, by SAS theorem, we have
Δ BFC ≅ Δ CEB
BE = CF (By c.p.c.t)
Similarly, AB = BE
Therefore, AD = BE = CF
Hence, proved
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