AD is the median of traingle ABC on base BC.if angle ADC =90 degree prove that traingle ABC is isosceles.
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when it is proved that AB=AC then it is isoceles
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To Prove: ΔABC is an isosceles triangle in which AB = AC.
In ΔADC and ΔADB,
AD = AD (Common)
∠ADC = ∠ADB (Each 90°)
CD = BD (AD is the perpendicular bisector of BC)
∴ ΔADC ≅ ΔADB (By SAS congruence rule)
∴ AB = AC (By CPCT)
Therefore, ABC is an isosceles triangle in which AB = AC
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