Question

AD is the median of triangle ABC . E is the mid - point of AD. BE produced
to meet AC at F. DG || BF Show that AC=3AF​

Answer 1

Answer:

AD is the median of ΔABC and E is the midpoint of AD

Through D draw DG∣∣BF

In ΔADG

E is the midpoint of AD and EF∣∣DG

By converse of midpoint theorem we have

F is midpoint of AG and AF=FG

Similarly, in ΔBCF

D is the midpoint of BC and DG∣∣BF

G is midpoint of CF and FG=GC

From equations 1 and 2

we will get

AF=FG=GC

AF+FG+GC=AC

AF+AF+AF=AC ...from eq 3

AF=AC

AF=(1/3)AC

Answer 2

Answer:

AF=AC

AF=(1/3)AC

Step-by-step explanation:

Hope it's correct thank you ♡