Question

AD is the median of triangle ABC. If ar (AABC) = 50 cm?, then ar (AABD) is


pls explain ​

Answer 1

Step-by-step explanation:

Since AD is the median The triangle is divided into two equal parts

ar(ABD)=50/2=25cm

Answer 2

Step-by-step explanation:

Given: AD is the median of triangle ABC. If ar (∆ABC) = 50 cm².

To find: Area of ∆ABD.

Solution:

We know that each median of a triangle divides the triangle in two equal parts.

i. e. area of both parts are equal.

here

Ar(∆ABC)= 50 cm²

As, median AD divides the triangle in two equal parts.

Thus,

$ar(∆ABD)=ar(∆ACD) = \frac{ar(∆ABC)}{2}$

Thus,

$ar(∆ABD)=ar(∆ACD) = \frac{50}{2} \: {cm}^{2}$

or

$ar(∆ABD)=ar(∆ACD) =25 \: {cm}^{2}$

Final answer:

$\bf ar(∆ABD) = 25 \: {cm}^{2}$

Hope it will help you.

Learn more:

1) In the figure,the line CE is parallel to BD area of triangle ABD is 30sq.cm and that of BDC is 29sq.cm?

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2) sides of two similar triangle are in the ratio of 4:9 corresponding median of these triangle are in the ratio

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