Question

AD is the median of triangle ABC.If ar(ACD)=50cm^(2) then ar(ABC)=​

Answer 1

Step-by-step explanation:

Given: AD is the median of triangle ABC. If ar (∆ABC) = 50 c

To find: Area of ∆ABD.

Solution:

We know that each median of a triangle divides the triangle in two equal parts.

i. e. area of both parts are equal.

here

Ar(∆ABC)= 50 cm²

As, median AD divides the triangle in two equal parts.

Thus,

\begin{gathered}ar(∆ABD)=ar(∆ACD) = \frac{ar(∆ABC)}{2} \\ \end{gathered}

ar(∆ABD)=ar(∆ACD)=

2

ar(∆ABC)

Thus,

\begin{gathered}ar(∆ABD)=ar(∆ACD) = \frac{50}{2} \: {cm}^{2} \\ \end{gathered}

ar(∆ABD)=ar(∆ACD)=

2

50

cm

2

or

\begin{gathered}ar(∆ABD)=ar(∆ACD) =25 \: {cm}^{2} \\ \end{gathered}

ar(∆ABD)=ar(∆ACD)=25cm

2

Final answer:

\begin{gathered}\bf ar(∆ABD) = 25 \: {cm}^{2} \\ \end{gathered}

ar(∆ABD)=25cm

2