AD =X, AE =X +3,DB=X+1,EC =X+10.FIND X IF DE IS PARALLEL TO BC
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If DE is parallel to BC
then by B.P.T.
AD/BD=AE/EC
X/X+1=X+3/X+10
X(X+10)=X+3(X+1)
X^2+10X=X^2+X+3X+3
X^2+10X=X^2+4X+3
X^2+10X-X^2-4X=3
6X=3
X=3/6
X=1/2 OR 0.5
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